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{ newleft = imagewidth * 4; if(left + newleft > 0) { newleft = -left; } imagelist_scrolleft('imagelistthumb', left, newleft, 'add'); imagelist_scrolleft('currentpic', curleft, newleft, 'add'); } } } function imagelist_scrolleft(id, left, num, type) { if(type == 'add') { left += num; } else { left -= num; } $(id).style.left = left +'px'; } function current_pic(n) { curnum = n; var left = parseInt($('imagelistthumb').style.left.substr(0, ($('imagelistthumb').style.left.length - 2))); $('pic').src=imglist['url'][n]; var curleft = imagewidth * n; if(imagecount > 7 && n >= 4) { if(n < (imagecount - 4)) { curleft = imagewidth * 3; imagelist_scrolleft('imagelistthumb', 0, imagewidth * (n-3)); } else { curleft = imagewidth * (7 - (imagecount - n)); imagelist_scrolleft('imagelistthumb', 0, imagewidth * (imagecount-7)); } } else { imagelist_scrolleft('imagelistthumb', 0, 0); } $('currentpic').style.left = curleft+'px'; }var imagelistkey = '857c826498258529'; var imglist = new Array(); var 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$('sharenumber').innerHTML + ' 人分享'"><i><img src="static/image/common/oshr.png" alt="分享" />分享<span id="sharenumber">0</span></i></a> <a href="http://club.oecr.com/home.php?mod=spacecp&ac=favorite&type=thread&id=172533" id="k_favorite" onclick="showWindow(this.id, this.href, 'get', 0);" onmouseover="this.title = $('favoritenumber').innerHTML + ' 人收藏'"><i><img src="static/image/common/fav.gif" alt="收藏" />收藏<span id="favoritenumber">0</span></i></a> <a id="recommend_add" href="forum.php?mod=misc&action=recommend&do=add&tid=172533&hash=cb42f05e" onclick="showWindow('login', this.href)" onmouseover="this.title = $('recommendv_add').innerHTML + ' 人支持'"><i><img src="static/image/common/rec_add.gif" alt="支持" />支持<span id="recommendv_add">0</span></i></a> <a id="recommend_subtract" href="forum.php?mod=misc&action=recommend&do=subtract&tid=172533&hash=cb42f05e" onclick="showWindow('login', this.href)" onmouseover="this.title = $('recommendv_subtract').innerHTML + ' 人反对'"><i><img src="static/image/common/rec_subtract.gif" alt="反对" />反对<span id="recommendv_subtract">0</span></i></a> </div> </td> <td valign="top" class="album_side_r"> <div class="album_side"> <div class="hm mtn mbn"> <a href="http://club.oecr.com/space-uid-65503.html" target="_blank" class="xi2"><img src="http://www.oecr.com/uc_server/avatar.php?uid=65503&size=small" /></a> <span class="tit_author"> <a href="http://club.oecr.com/space-uid-65503.html">甘1</a> </span> </div> <div class="date"><span>发布时间:</span> 2011-6-22 10:22</div> <div class="album_info"> <h3>正文摘要: </h3> <p>这个问题估计很菜鸟吧，麻烦大家帮忙解释一下。 LD端泵腔内倍频激光器，就拿绿光来说，为什么倍频晶体放置方向有如下两种啊？根据什么定的呢？ </p> </div> </div> </td> </tr> </table> </div> </div> <div class="bm vw pl" id="comment"> <div class="bm_h cl"> <h2>回复</h2> </div> <div class="bm_c"> <div id="postlistreply" class="xld xlda mbm"><div id="post_new" class="viewthread_table" style="display: none"></div></div><div id="post_833363" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-129341.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=129341&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-129341.html" target="_blank" class="xi2">chaser5623</a><em id="author_833363"> 发表于</em> <span class="xg1 xw0">2011-7-5 10:05:00</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_833363"> 出光了再说，再调角度</td></tr></table> </div> <div id="comment_833363" class="cm"> </div> <div id="post_rate_div_833363"></div> </div> </dd> </dl> </div> <div id="post_830860" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-65503.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=65503&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-65503.html" target="_blank" class="xi2">甘1</a><em id="author_830860"> 发表于</em> <span class="xg1 xw0">2011-7-1 11:27:45</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_830860"> 呵呵，概念越来越清晰了<img src="static/image/smiley/Tiger/07.gif" smilieid="145" border="0" alt="" /></td></tr></table> </div> <div id="comment_830860" class="cm"> </div> <div id="post_rate_div_830860"></div> </div> </dd> </dl> </div> <div id="post_830410" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-68245.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=68245&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-68245.html" target="_blank" class="xi2">bai3697</a><em id="author_830410"> 发表于</em> <span class="xg1 xw0">2011-6-30 21:46:34</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_830410"> KTP倍频采用II类位相匹配方式（90,23.5），如果你用的是Nd：YVO4，出射的激光是线偏光，所以KTP需要45°放置，效率最高；如果采用Nd：YAG作为激光晶体，就不用了。</td></tr></table> </div> <div id="comment_830410" class="cm"> </div> <div id="post_rate_div_830410"></div> </div> </dd> </dl> </div> <div id="post_830196" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-100819.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=100819&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-100819.html" target="_blank" class="xi2">腐子</a><em id="author_830196"> 发表于</em> <span class="xg1 xw0">2011-6-30 10:41:47</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_830196"> 非线性晶体都有个相位匹配和角度匹配的问题，可以去了解下，不过好像我们实验用的倍频晶体的匹配角都是加工好了的。我们这儿都是直接垂直光学面入射就出倍频光了。</td></tr></table> </div> <div id="comment_830196" class="cm"> </div> <div id="post_rate_div_830196"></div> </div> </dd> </dl> </div> <div id="post_829854" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-83803.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=83803&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-83803.html" target="_blank" class="xi2">弥勒</a><em id="author_829854"> 发表于</em> <span class="xg1 xw0">2011-6-29 14:36:26</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_829854"> 两种不同的安装结构，很显然右边的装卸比较方便，对晶体的稳固效果也更好。左边的若间隙太紧很难放下去，太松的话稳定性又不好，拆卸晶体是也比较麻烦。如果很容易就拆下来的话，晶体基本上是没有被夹紧的。激光器出场后返修和退货就很正常了。</td></tr></table> <div class="pattl"> <ignore_js_op> <dl class="tattl attm"> <dt></dt> <dd> <p class="mbn"> <a href="http://bbs.oecr.com/forum.php?mod=attachment&aid=NjQwMjJ8YjA0ZGRkOTh8MTc2NjcxODU2N3wwfDE3MjUzMw%3D%3D&nothumb=yes" onmouseover="showMenu({'ctrlid':this.id,'pos':'12'})" id="aid64022" class="xw1" target="_blank">1.jpg</a> <em class="xg1">(20.25 KB, 下载次数: 62)</em> </p> <div class="tip tip_4" id="aid64022_menu" style="display: none" disautofocus="true"> <div> <p> <a href="http://bbs.oecr.com/forum.php?mod=attachment&aid=NjQwMjJ8YjA0ZGRkOTh8MTc2NjcxODU2N3wwfDE3MjUzMw%3D%3D&nothumb=yes" target="_blank">下载附件</a> <a href="javascript:;" onclick="showWindow(this.id, this.getAttribute('url'), 'get', 0);" id="savephoto_64022" url="home.php?mod=spacecp&ac=album&op=saveforumphoto&aid=64022&handlekey=savephoto_64022">保存到相册</a> </p> <p> <span class="y">2011-6-29 14:23 上传</span> <a href="javascript:;" onclick="imageRotate('aimg_64022', 1)"><img src="static/image/common/rleft.gif" class="vm" /></a> <a href="javascript:;" onclick="imageRotate('aimg_64022', 2)"><img src="static/image/common/rright.gif" class="vm" /></a> </p> </div> <div class="tip_horn"></div> </div> <p class="mbn"> </p> <div class="mbn savephotop"> <img id="aimg_64022" aid="64022" src="static/image/common/none.gif" zoomfile="data/attachment/forum/201106/29/142357ia6twn6fppbnqwn9.jpg" file="data/attachment/forum/201106/29/142357ia6twn6fppbnqwn9.jpg" class="zoom" onclick="zoom(this, this.src, 0, 0, 0)" width="98" alt="1.jpg" title="1.jpg" w="720" /> </div> </dd> </dl> </ignore_js_op> </div> </div> <div id="comment_829854" class="cm"> </div> <div id="post_rate_div_829854"></div> </div> </dd> </dl> <script type="text/javascript" reload="1"> aimgcount[829854] = ['64022']; attachimggroup(829854); </script> </div> <div id="post_829825" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-65503.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=65503&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-65503.html" target="_blank" class="xi2">甘1</a><em id="author_829825"> 发表于</em> <span class="xg1 xw0">2011-6-29 13:26:14</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_829825"> <div class="quote"><blockquote><font size="2"><font color="#999999">lzk 发表于 2011-6-29 11:12</font> <a href="http://bbs.oecr.com/forum.php?mod=redirect&goto=findpost&pid=829781&ptid=172533" target="_blank"><img id="aimg_o5sh5" onclick="zoom(this, this.src, 0, 0, 0)" class="zoom" file="static/image/common/back.gif" onmouseover="img_onmouseoverfunc(this)" lazyloadthumb="1" border="0" alt="" /></a></font><br /> 楼主采用的是KTP晶体材料进行倍频还是LBO？如果是KTP的话就是加工时的Z轴角度的问题了。如果是常规腔外倍频 ...</blockquote></div><br /> 说的挺好的，谢谢你！</td></tr></table> </div> <div id="comment_829825" class="cm"> </div> <div id="post_rate_div_829825"></div> </div> </dd> </dl> <script type="text/javascript" reload="1"> aimgcount[829825] = ['o5sh5']; attachimggroup(829825); </script> </div> <div id="post_829781" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-5284.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=5284&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-5284.html" target="_blank" class="xi2">lzk</a><em id="author_829781"> 发表于</em> <span class="xg1 xw0">2011-6-29 11:12:47</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_829781"> 楼主采用的是KTP晶体材料进行倍频还是LBO？如果是KTP的话就是加工时的Z轴角度的问题了。如果是常规腔外倍频都是45度放置。也就是说加工时Z轴和对角线成45度。 如果是腔内的话就看客户自己的要求了。如果是V型槽放置的话就说明Z轴和对角线平行。希望能明白了。</td></tr></table> </div> <div id="comment_829781" class="cm"> </div> <div id="post_rate_div_829781"></div> </div> </dd> </dl> </div> <div id="post_828040" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-65503.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=65503&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-65503.html" target="_blank" class="xi2">甘1</a><em id="author_828040"> 发表于</em> <span class="xg1 xw0">2011-6-24 17:04:22</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_828040"> <i class="pstatus"> 本帖最后由 甘1 于 2011-6-24 17:04 编辑 </i><br /> <div class="quote"><blockquote><font size="2"><font color="#999999">kkkyt 发表于 2011-6-24 14:29</font> <a href="http://bbs.oecr.com/forum.php?mod=redirect&goto=findpost&pid=827967&ptid=172533" target="_blank"><img id="aimg_GdZNN" onclick="zoom(this, this.src, 0, 0, 0)" class="zoom" file="static/image/common/back.gif" onmouseover="img_onmouseoverfunc(this)" lazyloadthumb="1" border="0" alt="" /></a></font><br /> 已经够简练了。你自己不懂也没办法。去看一下非线性光学吧。</blockquote></div><br /> <br /> 你说的那些，意思我明白了，只是想听听有没有别的扩展的内容</td></tr></table> </div> <div id="comment_828040" class="cm"> </div> <div id="post_rate_div_828040"></div> </div> </dd> </dl> <script type="text/javascript" reload="1"> aimgcount[828040] = ['GdZNN']; attachimggroup(828040); </script> </div> <div id="post_827967" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-18999.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=18999&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-18999.html" target="_blank" class="xi2">kkkyt</a><em id="author_827967"> 发表于</em> <span class="xg1 xw0">2011-6-24 14:29:12</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_827967"> 已经够简练了。你自己不懂也没办法。去看一下非线性光学吧。</td></tr></table> </div> <div id="comment_827967" class="cm"> </div> <div id="post_rate_div_827967"></div> </div> </dd> </dl> </div> <div id="post_827964" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-65503.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=65503&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-65503.html" target="_blank" class="xi2">甘1</a><em id="author_827964"> 发表于</em> <span class="xg1 xw0">2011-6-24 14:25:56</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_827964"> 有没有人能简练解答的呢<img src="static/image/smiley/Tiger/05.gif" smilieid="143" border="0" alt="" /></td></tr></table> </div> <div id="comment_827964" class="cm"> </div> <div id="post_rate_div_827964"></div> </div> </dd> </dl> </div> <div id="post_827519" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-120646.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=120646&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-120646.html" target="_blank" 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