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src="static/image/common/oshr.png" alt="分享" />分享<span id="sharenumber">0</span></i></a> <a href="http://club.oecr.com/home.php?mod=spacecp&ac=favorite&type=thread&id=260229" id="k_favorite" onclick="showWindow(this.id, this.href, 'get', 0);" onmouseover="this.title = $('favoritenumber').innerHTML + ' 人收藏'"><i><img src="static/image/common/fav.gif" alt="收藏" />收藏<span id="favoritenumber">0</span></i></a> <a id="recommend_add" href="forum.php?mod=misc&action=recommend&do=add&tid=260229&hash=d4b7218d" onclick="showWindow('login', this.href)" onmouseover="this.title = $('recommendv_add').innerHTML + ' 人支持'"><i><img src="static/image/common/rec_add.gif" alt="支持" />支持<span id="recommendv_add">0</span></i></a> <a id="recommend_subtract" href="forum.php?mod=misc&action=recommend&do=subtract&tid=260229&hash=d4b7218d" onclick="showWindow('login', this.href)" onmouseover="this.title = $('recommendv_subtract').innerHTML + ' 人反对'"><i><img src="static/image/common/rec_subtract.gif" alt="反对" />反对<span id="recommendv_subtract">0</span></i></a> </div> </td> <td valign="top" class="album_side_r"> <div class="album_side"> <div class="hm mtn mbn"> <a href="http://club.oecr.com/space-uid-110997.html" target="_blank" class="xi2"><img src="http://www.oecr.com/uc_server/avatar.php?uid=110997&size=small" /></a> <span class="tit_author"> <a href="http://club.oecr.com/space-uid-110997.html">音乐之声</a> </span> </div> <div class="date"><span>发布时间:</span> 2013-9-6 09:08</div> <div class="album_info"> <h3>正文摘要: </h3> <p>请教！LBO激光晶体应满足哪些条件，基频光（1064nm)直接通过LBO倍频晶体而不会发生倍频转换？</p> </div> </div> </td> </tr> </table> </div> </div> <div class="bm vw pl" id="comment"> <div class="bm_h cl"> <h2>回复</h2> </div> <div class="bm_c"> <div id="postlistreply" class="xld xlda mbm"><div id="post_new" class="viewthread_table" style="display: none"></div></div><div id="post_1104725" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-110997.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=110997&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-110997.html" target="_blank" class="xi2">音乐之声</a><em id="author_1104725"> 发表于</em> <span class="xg1 xw0">2013-11-17 12:01:53</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1104725"> <div class="quote"><blockquote><font size="2"><font color="#999999">bai3697 发表于 2013-9-15 17:04</font> <a href="http://bbs.oecr.com/forum.php?mod=redirect&goto=findpost&pid=1098999&ptid=260229" target="_blank"><img id="aimg_DVLAa" onclick="zoom(this, this.src, 0, 0, 0)" class="zoom" file="static/image/common/back.gif" onmouseover="img_onmouseoverfunc(this)" lazyloadthumb="1" border="0" alt="" /></a></font><br /> 从你上的图来看，一般LBO II类和频（1064+532）的匹配角度为（theta，phi）42.5，90度，而LBO倍频的多采用I ...</blockquote></div><br /> 谢谢你的指点，问题在于相位匹配啊！！！</td></tr></table> </div> <div id="comment_1104725" class="cm"> </div> <div id="post_rate_div_1104725"></div> </div> </dd> </dl> <script type="text/javascript" reload="1"> aimgcount[1104725] = ['DVLAa']; attachimggroup(1104725); </script> </div> <div id="post_1099079" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-55229.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=55229&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-55229.html" target="_blank" class="xi2">lf688</a><em id="author_1099079"> 发表于</em> <span class="xg1 xw0">2013-9-16 12:07:28</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1099079"> 13楼回答的很正确，<img src="static/image/smiley/Tiger/05.gif" smilieid="143" border="0" alt="" /><img src="static/image/smiley/Tiger/05.gif" smilieid="143" border="0" alt="" /><img src="static/image/smiley/Tiger/05.gif" smilieid="143" border="0" alt="" /><br /> 从你上的图来看，一般LBO II类和频（1064+532）的匹配角度为（theta，phi）42.5，90度，而LBO倍频的多采用I类，角度（theta，phi）90，11.3度，所以和频晶体不会满足相位匹配，也就不会倍频。也就是说从1端入射进来的1064不会转换，也就是楼上说的相当于块玻璃。1端切成布儒斯特角也一样，跟镀膜没有本质区别</td></tr></table> </div> <div id="comment_1099079" class="cm"> </div> <div id="post_rate_div_1099079"></div> </div> </dd> </dl> </div> <div id="post_1098999" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-68245.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=68245&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-68245.html" target="_blank" class="xi2">bai3697</a><em id="author_1098999"> 发表于</em> <span class="xg1 xw0">2013-9-15 17:04:39</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1098999"> 从你上的图来看，一般LBO II类和频（1064+532）的匹配角度为（theta，phi）42.5，90度，而LBO倍频的多采用I类，角度（theta，phi）90，11.3度，所以和频晶体不会满足相位匹配，也就不会倍频。也就是说从1端入射进来的1064不会转换，也就是楼上说的相当于块玻璃。1端切成布儒斯特角也一样，跟镀膜没有本质区别</td></tr></table> </div> <div id="comment_1098999" class="cm"> </div> <div id="post_rate_div_1098999"></div> </div> </dd> </dl> </div> <div id="post_1098806" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-50282.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=50282&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-50282.html" target="_blank" class="xi2">xbdxwm</a><em id="author_1098806"> 发表于</em> <span class="xg1 xw0">2013-9-13 15:25:50</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1098806"> <div class="quote"><blockquote><font size="2"><font color="#999999">音乐之声 发表于 2013-9-11 22:47</font> <a href="http://bbs.oecr.com/forum.php?mod=redirect&goto=findpost&pid=1098570&ptid=260229" target="_blank"><img id="aimg_WSt8t" onclick="zoom(this, this.src, 0, 0, 0)" class="zoom" file="static/image/common/back.gif" onmouseover="img_onmouseoverfunc(this)" lazyloadthumb="1" border="0" alt="" /></a></font><br /> 说的不太明白，上图</blockquote></div><br /> 腔内和频紫外啊，你这和频晶体已经不满足相位匹配了，它不会倍频了，就当他是块玻璃吧。</td></tr></table> </div> <div id="comment_1098806" class="cm"> <h3 class="psth xs1"><span class="icon_ring vm"></span>点评</h3> <div class="pstl xs1 cl"> <div class="psta vm"> <a href="http://club.oecr.com/space-uid-110997.html" c="1"><img src="http://www.oecr.com/uc_server/avatar.php?uid=110997&size=small" /></a> <a href="http://club.oecr.com/space-uid-110997.html" class="xi2 xw1">音乐之声</a> </div> <div class="psti"> 是腔内和频紫外，我就是不明白两块晶体这样放置是什么个原理？那如果它的1端面采用布儒斯特角切割，基频光又以一定的角度入射，那它还是一块玻璃吗？ <span class="xg1"> 发表于 2013-9-13 16:53</span> </div> </div> </div> <div id="post_rate_div_1098806"></div> </div> </dd> </dl> <script type="text/javascript" reload="1"> aimgcount[1098806] = ['WSt8t']; attachimggroup(1098806); </script> </div> <div id="post_1098735" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-131215.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=131215&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-131215.html" target="_blank" class="xi2">小鸟儿</a><em id="author_1098735"> 发表于</em> <span class="xg1 xw0">2013-9-13 08:35:29</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1098735"> 论坛冷清很久了</td></tr></table> </div> <div id="comment_1098735" class="cm"> </div> <div id="post_rate_div_1098735"></div> </div> </dd> </dl> </div> <div id="post_1098728" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-18999.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=18999&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-18999.html" target="_blank" class="xi2">kkkyt</a><em id="author_1098728"> 发表于</em> <span class="xg1 xw0">2013-9-13 08:17:37</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1098728"> 你可以忽略1的 倍频。你可以把2去掉用532输出镜看1有多少绿光。。。。。</td></tr></table> </div> <div id="comment_1098728" class="cm"> </div> <div id="post_rate_div_1098728"></div> </div> </dd> </dl> </div> <div id="post_1098708" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-155269.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=155269&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-155269.html" target="_blank" class="xi2">风语漂泊0</a><em id="author_1098708"> 发表于</em> <span class="xg1 xw0">2013-9-13 04:51:23</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1098708"> 学习学习</td></tr></table> </div> <div id="comment_1098708" class="cm"> </div> <div id="post_rate_div_1098708"></div> </div> </dd> </dl> </div> <div id="post_1098082" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-83803.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=83803&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-83803.html" target="_blank" class="xi2">弥勒</a><em id="author_1098082"> 发表于</em> <span class="xg1 xw0">2013-9-10 09:24:38</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1098082"> 不转换？用LBO做什么？</td></tr></table> </div> <div id="comment_1098082" class="cm"> </div> <div id="post_rate_div_1098082"></div> </div> </dd> </dl> </div> <div id="post_1098067" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-18999.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=18999&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-18999.html" target="_blank" class="xi2">kkkyt</a><em id="author_1098067"> 发表于</em> <span class="xg1 xw0">2013-9-10 08:48:30</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1098067"> 你。。角度不对就可以了。</td></tr></table> </div> <div id="comment_1098067" class="cm"> </div> <div id="post_rate_div_1098067"></div> </div> </dd> </dl> </div> <div id="post_1097846" class="xld xlda mbm"><dl class="bbda cl"> <dd class="m avt"><a href="http://club.oecr.com/space-uid-126196.html"><img src="http://www.oecr.com/uc_server/avatar.php?uid=126196&size=small" /></a></dd> <dt> <span class="y xw0"> </span> <a href="http://club.oecr.com/space-uid-126196.html" target="_blank" class="xi2">wangliia</a><em id="author_1097846"> 发表于</em> <span class="xg1 xw0">2013-9-9 15:52:18</span> </dt> <dd class="z"><div class="pcb"> <div class="t_fsz"> <table cellspacing="0" cellpadding="0"><tr><td class="t_f" id="postmessage_1097846"> 不匹配就行了，或者说可以匹配的那种，LBO转个90°也行</td></tr></table> </div> <div id="comment_1097846" class="cm"> </div> <div id="post_rate_div_1097846"></div> </div> </dd> </dl> </div> </div> </div> </div> <script type="text/javascript"> new lazyload(); </script> <div class="wp mtn"> <!--[diy=diy3]--><div id="diy3" class="area"></div><!--[/diy]--> </div></div> </div> <!--autocomment filter by maxnum--> <div class="ft_wp"> <div id="ft" class=" cl"> <div id="flk" > <p> <a href="http://wpa.qq.com/msgrd?V=3&Uin=20600600&Site=光电工程师社区&Menu=yes&from=discuz" target="_blank" title="QQ"><img src="static/image/common/site_qq.jpg" alt="QQ" /></a><span class="pipe">|</span><a href="http://m.oecr.com" 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