各位进行AUT时可成遇到这样的问题？

victorrose · 发表于 2004-8-30 06:54:00

如下图所示，为了加工上的需要，需在光线有效径外预留约0.2MM的长度。小弟使用下列两种方式限制光线有效径外约0.2MM处的边缘厚度，可是得到的结果却不同，何以如此？






限制条件1在光线有效径外预留约<st1:chmetcnv w:st="on" TCSC="0" NumberType="1" Negative="False" HasSpace="False" SourceValue="0.21" UnitName="mm">0.21MM</st1:chmetcnv>的长度


@edge==(CT S11 Z1)+(SAGF(12,1,0,((SD S12 Z1)+0.21)))-(SAGF(11,1,0,((SD S11 Z1)+0.21)))


@edge 0.6





优化结果检验(如左下图)
wri (CT S11 Z1)+(SAGF(12,1,0,((SD S12 Z1)+0.21)))-(SAGF(11,1,0,((SD S11 Z1)+0.21)))
 0.600132








限制条件2在光线有效径外预留约<st1:chmetcnv w:st="on" TCSC="0" NumberType="1" Negative="False" HasSpace="False" SourceValue="0.2" UnitName="mm">0.2MM</st1:chmetcnv>的长度,并在小数点以下2位之后无条件进位（因为加工图的图面只标示至小数点以下第二位）


@edge==((CT s11 Z1)+(SAGF(12,1,0,((SD s12 Z1)-modf((SD s12 Z1),0.01)+0.21)))-(SAGF(11,1,0,((SD s11 Z1)-modf((SD s11 Z1),0.01)+0.21))))


@edge 0.6





优化结果检验(如右下图)
wri ((CT s11 Z1)+(SAGF(12,1,0,((SD s12 Z1)-modf((SD s12 Z1),0.01)+0.21)))-(SAGF(11,1,0,((SD s11 Z1)-modf((SD s11 Z1),0.01)+0.21))))
 0.492663

<img src="data/attachment/forum/dvbbs/2004-8/2004829225423867.gif" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor=\'hand\'; this.alt=\'Click here to open new window\nCTRL+Mouse wheel to zoom in/out\';}" onclick="if(!this.resized) {return true;} else {window.open(\'data/attachment/forum/dvbbs/2004-8/2004829225423867.gif\');}" onmousewheel="return imgzoom(this);" alt="" />

redflag · 发表于 2004-8-30 16:50:00

你的计算边厚的公式好像有点问题. 对球面是对的,对非球面不一定准确.可能要根据条件判断一下.

victorrose · 发表于 2004-8-31 06:38:00

版主您好，能否在说明更详尽些，因为实在不明白，谢谢

nytang · 发表于 2004-8-31 17:32:00

I believe your first equation is correct. But I could not understand why you want to write it as equation 2? The other question is that is it reasonable the calculation apears in the bracket after the pre-defined function?

victorrose · 发表于 2004-9-2 05:21:00

再说明如下限制条件1是在光线有效径外的<st1:chmetcnv UnitName="mm" SourceValue="0.21" HasSpace="False" Negative="False" NumberType="1" TCSC="0" w:st="on">0.21MM</st1:chmetcnv>处作计算。限制条件2是在光线有效径加<st1:chmetcnv UnitName="mm" SourceValue="0.2" HasSpace="False" Negative="False" NumberType="1" TCSC="0" w:st="on">0.20MM</st1:chmetcnv>后，小数点2位以下之后进位。另外，此两限制条件无同时存在，先使用限制条件1。之后，将限制条件1删除，使用限制条件2。

nytang · 发表于 2004-9-3 17:16:00

那你的公式應該改為modf((sd s11 z1), 100) 吧

victorrose · 发表于 2004-9-4 16:46:00

command line

wri (modf(1.23456789,0.01)) 0.00456789 ==================================

wri (1.23456789-modf(1.23456789,0.01)) 1.23

各位进行AUT时可成遇到这样的问题？

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