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<p>■■■问题<br/>1.要计算某特定像高(field)的MTF时,是否一定要计算所有像高的MTF,然后由buffer中去搜寻?<br/>2.以下「自行创建的macro」是否可再修改更精简?</p><p>■■■使用的档案cooke1.len<br/>RES cv_lens:cooke1.len</p><p>■■■执行自行创建的macro<br/>in "C:\optics\CODEV940\macro\my_macro\mtf__one_field__input_fieldno_freq.seq" 2 30</p><p>■■■macro内容如下<br/>! Purpose: To compute the MTF of a given field and spatial frequency</p><p>!***************************************************************************<br/>! arg0 "Macro to calculate the MTF of a given field and spatial frequency"<br/>!<br/>! arg1 name "field no."<br/>! arg1 type num<br/>! arg1 default 0<br/>! arg1 help "field no."<br/>!<br/>! arg2 name "Spatial Frequency (lp/mm)"<br/>! arg2 type num<br/>! arg2 default 0<br/>! arg2 help "MTF spatial frequency used to calculate the MTF"<br/>!*****************************************************************************<br/>lcl num ^freq<br/>lcl num ^i ^j ^jj<br/>lcl num ^mtfs(25,18)<br/>lcl num ^mtft(25,18)</p><p>ver n<br/>^field_no == #1<br/>^freq == #2</p><p>if ^field_no (num f)<br/> wri "Maximum field number is :" (num f)<br/> rtn<br/>end if</p><p>out n<br/>buf del b0<br/>buf<br/>mtf<br/>mfr ^freq<br/>ifr ^freq<br/>plo fre n<br/>go<br/>buf n<br/>out y</p><p>for ^i 1 ^field_no<br/> buf fnd b0 "DIFFRACTION LIMIT"<br/> buf mov b0 ic+5<br/>end for</p><p>^j == 4+(nfo)<br/>^frequency == (buf.num b0 ic j1)<br/>^mtfs(^i,^j) == (buf.num b0 ic j^j)<br/>^mtft(^i,^j+1) == (buf.num b0 ic j^j+1)</p><p>wri q"(nfo)= '2d' ,^i= '2d' ,^j= '2d'" (nfo) ^i ^j<br/>wri q"field= '2d' ,^frequency= '3d' ,^mtfs('2d','2d')= 'd.3d'" ^field_no ^frequency ^i ^j ^mtfs(^i,^j)<br/>wri q"field= '2d' ,^frequency= '3d' ,^mtft('2d','2d')= 'd.3d'" ^field_no ^frequency ^i ^j+1 ^mtft(^i,^j+1)</p><p>!■ Delete the buffer<br/>out n<br/>buf del b0<br/>out y</p><p>go</p><p>■■■结果<br/>(nfo)= 1 ,^i= 3 ,^j= 5<br/>field= 2 ,^frequency= 30 ,^mtfs( 3, 5)= 0.088<br/>field= 2 ,^frequency= 30 ,^mtft( 3, 6)= 0.367</p>
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